MathematicsMedium249×since 2002Q2492The shortest distance between the lines x−33=y−8−1=z−31{{x - 3} \over 3} = {{y - 8} \over { - 1}} = {{z - 3} \over 1}3x−3=−1y−8=1z−3 and x+3−3=y+72=z−64{{x + 3} \over { - 3}} = {{y + 7} \over 2} = {{z - 6} \over 4}−3x+3=2y+7=4z−6 is :A3B7230{7 \over 2}\sqrt {30}2730C3303\sqrt {30}330D2302\sqrt {30}230Check answerSkip