MathematicsMedium249×since 2002Q2518The shortest distance between the lines x+21=y−2=z−52{{x + 2} \over 1} = {y \over { - 2}} = {{z - 5} \over 2}1x+2=−2y=2z−5 and x−41=y−12=z+30{{x - 4} \over 1} = {{y - 1} \over 2} = {{z + 3} \over 0}1x−4=2y−1=0z+3 is :A8B7C6D9Check answerSkip