MathematicsMedium249×since 2002Q2508The shortest distance between the lines x−51=y−22=z−4−3{{x - 5} \over 1} = {{y - 2} \over 2} = {{z - 4} \over { - 3}}1x−5=2y−2=−3z−4 and x+31=y+54=z−1−5{{x + 3} \over 1} = {{y + 5} \over 4} = {{z - 1} \over { - 5}}1x+3=4y+5=−5z−1 is :A737\sqrt 373B535\sqrt 353C434\sqrt 343D636\sqrt 363Check answerSkip