MathematicsMedium249×since 2002Q2542The shortest distance between the lines x−32=y+15−7=z−95\frac{x-3}{2}=\frac{y+15}{-7}=\frac{z-9}{5}2x−3=−7y+15=5z−9 and x+12=y−11=z−9−3\frac{x+1}{2}=\frac{y-1}{1}=\frac{z-9}{-3}2x+1=1y−1=−3z−9 isA838 \sqrt{3}83B636 \sqrt{3}63C535 \sqrt{3}53D434 \sqrt{3}43Check answerSkip