MathematicsMedium249×since 2002Q2519The shortest distance between the lines x−44=y+25=z+33\frac{x-4}{4}=\frac{y+2}{5}=\frac{z+3}{3}4x−4=5y+2=3z+3 and x−13=y−34=z−42\frac{x-1}{3}=\frac{y-3}{4}=\frac{z-4}{2}3x−1=4y−3=2z−4 is :A363 \sqrt{6}36B626 \sqrt{2}62C636 \sqrt{3}63D262 \sqrt{6}26Check answerSkip