MathematicsMedium249×since 2002Q2505The shortest distance between the lines x+7−6=y−67=z\frac{x+7}{-6}=\frac{y-6}{7}=z−6x+7=7y−6=z and 7−x2=y−2=z−6\frac{7-x}{2}=y-2=z-627−x=y−2=z−6 is :A2292 \sqrt{29}229B1C3729\sqrt{\frac{37}{29}}2937D292\frac{\sqrt{29}}{2}229Check answerSkip