MathematicsMedium175×since 2002Q2756The shortest distance between line y−x=1y-x=1y−x=1 and curve x=y2x = {y^2}x=y2 isA328{{3\sqrt 2 } \over 8}832B832{8 \over {3\sqrt 2 }}328C43{4 \over {\sqrt 3 }}34D34{{\sqrt 3 } \over 4}43Check answerSkip