PhysicsEasy156×since 2002Q8320The resistance R=VIR=\frac{V}{I}R=IV where V=(200±5)V\mathrm{V}=(200 \pm 5) \mathrm{V}V=(200±5)V and I=(20±0.2)AI=(20 \pm 0.2) \mathrm{A}I=(20±0.2)A, the percentage error in the measurement of R\mathrm{R}R is :A5.5%B3%C7%D3.5%Check answerSkip