ChemistryEasy113×since 2002Q2115The radius of the second Bohr orbit, in terms of the Bohr radius, a₀, in Li²⁺ is :A2a09{{2{a_0}} \over 9}92a0B2a03{{2{a_0}} \over 3}32a0C4a09{{4{a_0}} \over 9}94a0D4a03{{4{a_0}} \over 3}34a0Check answerSkip