MathematicsEasy178×since 2002Q5315The product 214.4116.8148.161128{2^{{1 \over 4}}}{.4^{{1 \over {16}}}}{.8^{{1 \over {48}}}}{.16^{{1 \over {128}}}}241.4161.8481.161281 ... to ∞\infty∞ is equal to :A214{2^{{1 \over 4}}}241B212{2^{{1 \over 2}}}221C1D2Check answerSkip