MathematicsMedium128×since 2002Q5600The point (2, 1) is translated parallel to the line L : x− y = 4 by 232\sqrt 323 units. If the newpoint Q lies in the third quadrant, then the equation of the line passing through Q and perpendicular to L is :Ax + y = 2 −-− 6\sqrt 66Bx + y = 3 −-− 36\sqrt 66Cx + y = 3 −-− 26\sqrt 66D2x + 2y = 1 −-− 6\sqrt 66Check answerSkip