ChemistryEasy113×since 2002Q2188The orbital angular momentum for an electron revolving in an orbit is given by l(l+1)h2π\sqrt {l(l + 1)} {h \over {2\pi }}l(l+1)2πh. This momentum for an s-electron will be given byAzeroBh2π{h \over {2\pi }}2πhC2h2π\sqrt 2 {h \over {2\pi }}22πhD+12h2π+ {1 \over 2}{h \over {2\pi }}+212πhCheck answerSkip