MathematicsEasy66×since 2002Q4061The number of real roots of the equation tan−1x(x+1)+sin−1x2+x+1=π4{\tan ^{ - 1}}\sqrt {x(x + 1)} + {\sin ^{ - 1}}\sqrt {{x^2} + x + 1} = {\pi \over 4}tan−1x(x+1)+sin−1x2+x+1=4π is :A1B2C4D0Check answerSkip