MathematicsEasy175×since 2002Q2758The normal to the curve, x2+2xy−3y2=0{x^2} + 2xy - 3{y^2} = 0x2+2xy−3y2=0, at (1,1)(1,1)(1,1)Ameets the curve again in the third quadrant.Bmeets the curve again in the fourth quadrant.Cdoes not meet the curve again.Dmeets the curve again in the second quadrant.Check answerSkip