MathematicsMedium92×since 2002Q4702The normal at the point(bt12,2bt1)\left( {bt_1^2,2b{t_1}} \right)(bt12,2bt1) on a parabola meets the parabola again in the point (bt22,2bt2)\left( {bt_2^2,2b{t_2}} \right)(bt22,2bt2), then :At2=t1+2t1{t_2} = {t_1} + {2 \over {{t_1}}}t2=t1+t12Bt2=−t1−2t1{t_2} = -{t_1} - {2 \over {{t_1}}}t2=−t1−t12Ct2=−t1+2t1{t_2} = -{t_1} + {2 \over {{t_1}}}t2=−t1+t12Dt2=t1−2t1{t_2} = {t_1} - {2 \over {{t_1}}}t2=t1−t12Check answerSkip