MathematicsEasy115×since 2008Q4340The negation of the statement ∼p∧(p∨q)\sim p \wedge (p \vee q)∼p∧(p∨q) is :Ap∨∼qp \vee \sim qp∨∼qB∼p∨q\sim p \vee q∼p∨qC∼p∧q\sim p \wedge q∼p∧qDp∧∼qp \wedge \sim qp∧∼qCheck answerSkip