MathematicsEasy115×since 2008Q4395The negation of (p∧(∼q))∨(∼p)(p \wedge(\sim q)) \vee(\sim p)(p∧(∼q))∨(∼p) is equivalent to :Ap∧qp \wedge qp∧qBp∧(∼q)p \wedge(\sim q)p∧(∼q)Cp∧(q∧(∼p))p \wedge(q \wedge(\sim p))p∧(q∧(∼p))Dp∨(q∨(∼p))p \vee(q \vee(\sim p))p∨(q∨(∼p))Check answerSkip