MathematicsEasy178×since 2002Q5180The minimum value of f(x)=aax+a1−axf(x) = {a^{{a^x}}} + {a^{1 - {a^x}}}f(x)=aax+a1−ax, where a, x∈Rx \in Rx∈R and a > 0, is equal to :Aa+1aa + {1 \over a}a+a1B2aCa + 1D2a2\sqrt a2aCheck answerSkip