PhysicsEasy183×since 2002Q6012The magnetic moment of an electron (e) revolving in an orbit around nucleus with an orbital angular momentum is given by :Aμ⃗L=eL→2 m\vec{\mu}_{\mathrm{L}}=\frac{\overrightarrow{\mathrm{eL}}}{2 \mathrm{~m}}μL=2 meLBμ⃗L=−eL→2 m\vec{\mu}_{\mathrm{L}}=-\frac{\overrightarrow{\mathrm{eL}}}{2 \mathrm{~m}}μL=−2 meLCμ⃗l=−eL→ m\vec{\mu}_{l}=-\frac{\overrightarrow{e L}}{\mathrm{~m}}μl=− meLDμ⃗l=2eL→m\vec{\mu}_{l}=\frac{2 \overrightarrow{\mathrm{eL}}}{\mathrm{m}}μl=m2eLCheck answerSkip