MathematicsEasy74×since 2004Q3724The locus of mid-points of the line segments joining (−-−3, −-−5) and the points on the ellipse x24+y29=1{{{x^2}} \over 4} + {{{y^2}} \over 9} = 14x2+9y2=1 is :A9x2+4y2+18x+8y+145=09{x^2} + 4{y^2} + 18x + 8y + 145 = 09x2+4y2+18x+8y+145=0B36x2+16y2+90x+56y+145=036{x^2} + 16{y^2} + 90x + 56y + 145 = 036x2+16y2+90x+56y+145=0C36x2+16y2+108x+80y+145=036{x^2} + 16{y^2} + 108x + 80y + 145 = 036x2+16y2+108x+80y+145=0D36x2+16y2+72x+32y+145=036{x^2} + 16{y^2} + 72x + 32y + 145 = 036x2+16y2+72x+32y+145=0Check answerSkip