MathematicsMedium249×since 2002Q2459The line l1l_1l1 passes through the point (2, 6, 2) and is perpendicular to the plane 2x+y−2z=102x+y-2z=102x+y−2z=10. Then the shortest distance between the line l1l_1l1 and the line x+12=y+4−3=z2\frac{x+1}{2}=\frac{y+4}{-3}=\frac{z}{2}2x+1=−3y+4=2z is :A9B7C193\frac{19}{3}319D133\frac{13}{3}313Check answerSkip