MathematicsEasy249×since 2002Q2547The intersection of the spheres x2+y2+z2+7x−2y−z=13{x^2} + {y^2} + {z^2} + 7x - 2y - z = 13x2+y2+z2+7x−2y−z=13 and x2+y2+z2−3x+3y+4z=8{x^2} + {y^2} + {z^2} - 3x + 3y + 4z = 8x2+y2+z2−3x+3y+4z=8 is the same as the intersection of one of the sphere and the planeA2x−y−z=12x-y-z=12x−y−z=1Bx−2y−z=1x-2y-z=1x−2y−z=1Cx−y−2z=1x-y-2z=1x−y−2z=1Dx−y−z=1x-y-z=1x−y−z=1Check answerSkip