PhysicsMedium65×since 2002Q7833The instantaneous velocity of a particle moving in a straight line is given as V=αt+βt2V = \alpha t + \beta {t^2}V=αt+βt2, where α\alphaα and β\betaβ are constants. The distance travelled by the particle between 1s and 2s is :A3α\alphaα + 7β\betaβB32α+73β{3 \over 2}\alpha + {7 \over 3}\beta23α+37βCα2+β3{\alpha \over 2} + {\beta \over 3}2α+3βD32α+72β{3 \over 2}\alpha + {7 \over 2}\beta23α+27βCheck answerSkip