ChemistryEasy80×since 2002Q144The increasing order of stability of the following free radicals isA(C6H5)2C∙H{({C_6}{H_5})_2}\mathop C\limits^ \bullet H(C6H5)2C∙H < (C6H5)3C∙{({C_6}{H_5})_3}\mathop C\limits^ \bullet(C6H5)3C∙ < (CH3)3C∙{(C{H_3})_3}\mathop C\limits^ \bullet(CH3)3C∙ < (CH3)2C∙H{(C{H_3})_2}\mathop C\limits^ \bullet H(CH3)2C∙HB(CH3)2C∙H{(C{H_3})_2}\mathop C\limits^ \bullet H(CH3)2C∙H < (CH3)3C∙{(C{H_3})_3}\mathop C\limits^ \bullet(CH3)3C∙ < (C6H5)2C∙H{({C_6}{H_5})_2}\mathop C\limits^ \bullet H(C6H5)2C∙H < (C6H5)3C∙{({C_6}{H_5})_3}\mathop C\limits^ \bullet(C6H5)3C∙C(CH3)2C∙H{(C{H_3})_2}\mathop C\limits^ \bullet H(CH3)2C∙H < (CH3)3C∙{(C{H_3})_3}\mathop C\limits^ \bullet(CH3)3C∙ < (C6H5)3C∙{({C_6}{H_5})_3}\mathop C\limits^ \bullet(C6H5)3C∙ < (C6H5)2C∙H{({C_6}{H_5})_2}\mathop C\limits^ \bullet H(C6H5)2C∙HD(C6H5)3C∙{({C_6}{H_5})_3}\mathop C\limits^ \bullet(C6H5)3C∙ < (C6H5)2C∙H{({C_6}{H_5})_2}\mathop C\limits^ \bullet H(C6H5)2C∙H < (CH3)3C∙{(C{H_3})_3}\mathop C\limits^ \bullet(CH3)3C∙ < (CH3)2C∙H{(C{H_3})_2}\mathop C\limits^ \bullet H(CH3)2C∙HCheck answerSkip