PhysicsMedium159×since 2002Q7131The height at which the acceleration due to gravity becomes g9{g \over 9}9g (where g=g=g= the acceleration due to gravity on the surface of the earth) in terms of R,R,R, the radius of the earth, is:AR2{R \over {\sqrt 2 }}2RBR/2R/2R/2C2 R\sqrt 2 \,\,R2RD2 R2\,R2RCheck answerSkip