PhysicsEasy159×since 2002Q7176The escape velocity for a body projected vertically upwards from the surface of earth is 111111 km/s.km/s.km/s. If the body is projected at an angle of 45∘{45^ \circ }45∘ with the vertical, the escape velocity will beA112 km/s11\sqrt 2 \,\,km/s112km/sB222222 km/skm/skm/sC111111 km/skm/skm/sD112km/s{{11} \over {\sqrt 2 }}km/s211km/sCheck answerSkip