MathematicsMedium249×since 2002Q2573The equation of the plane containing the straight line x2=y3=z4{x \over 2} = {y \over 3} = {z \over 4}2x=3y=4z and perpendicular to the plane containing the straight lines x3=y4=z2{x \over 3} = {y \over 4} = {z \over 2}3x=4y=2z and x4=y2=z3{x \over 4} = {y \over 2} = {z \over 3}4x=2y=3z is :Ax −-− 2y + z = 0B3x + 2y −-− 3z = 0Cx + 2y −-− 2z = 0D5x + 2y −-− 4z = 0Check answerSkip