MathematicsHard249×since 2002Q2406The equation of the line passing through (–4, 3, 1), parallel to the plane x + 2y – z – 5 = 0 and intersecting the line x+1−3=y−32=z−2−1{{x + 1} \over { - 3}} = {{y - 3} \over 2} = {{z - 2} \over { - 1}}−3x+1=2y−3=−1z−2 is :Ax+43=y−3−1=z−11{{x + 4} \over 3} = {{y - 3} \over {-1}} = {{z - 1} \over 1}3x+4=−1y−3=1z−1Bx+41=y−31=z−13{{x + 4} \over 1} = {{y - 3} \over {1}} = {{z - 1} \over 3}1x+4=1y−3=3z−1Cx+4−1=y−31=z−11{{x + 4} \over -1} = {{y - 3} \over {1}} = {{z - 1} \over 1}−1x+4=1y−3=1z−1Dx−42=y+31=z+14{{x - 4} \over 2} = {{y + 3} \over {1}} = {{z + 1} \over 4}2x−4=1y+3=4z+1Check answerSkip