PhysicsMedium94×since 2002Q5911The equation of current in a purely inductive circuit is 5sin(49 πt−30∘)5 \sin \left(49\, \pi t-30^{\circ}\right)5sin(49πt−30∘). If the inductance is 30 mH30 \,\mathrm{mH}30mH then the equation for the voltage across the inductor, will be : {\left\{\right.{ Let π=227}\left.\pi=\frac{22}{7}\right\}π=722}A1.47sin(49πt−30∘)1.47 \sin \left(49 \pi t-30^{\circ}\right)1.47sin(49πt−30∘)B1.47sin(49πt+60∘)1.47 \sin \left(49 \pi t+60^{\circ}\right)1.47sin(49πt+60∘)C23.1sin(49πt−30∘)23.1 \sin \left(49 \pi t-30^{\circ}\right)23.1sin(49πt−30∘)D23.1sin(49πt+60∘)23.1 \sin \left(49 \pi t+60^{\circ}\right)23.1sin(49πt+60∘)Check answerSkip