MathematicsMedium74×since 2004Q3744The ellipse x2+4y2=4{x^2} + 4{y^2} = 4x2+4y2=4 is inscribed in a rectangle aligned with the coordinate axex, which in turn is inscribed in another ellipse that passes through the point (4,0)(4,0)(4,0). Then the equation of the ellipse is :Ax2+12y2=16{x^2} + 12{y^2} = 16x2+12y2=16B4x2+48y2=484{x^2} + 48{y^2} = 484x2+48y2=48C4x2+64y2=484{x^2} + 64{y^2} = 484x2+64y2=48Dx2+16y2=16{x^2} + 16{y^2} = 16x2+16y2=16Check answerSkip