PhysicsMedium46×since 2002Q7000The electrostatic potential inside a charged spherical ball is given by ϕ=ar2+b\phi = a{r^2} + bϕ=ar2+b where rrr is the distance from the center and a,ba,ba,b are constants. Then the charge density inside the ball is:A−6aε0r- 6a{\varepsilon _0}r−6aε0rB−24πaε0- 24\pi a{\varepsilon _0}−24πaε0C−6aε0- 6a{\varepsilon _0}−6aε0D−24πε0r- 24\pi {\varepsilon _0}r−24πε0rCheck answerSkip