Periodic Table and Periodicity

Question

The electronic configuration with the highest ionization enthalpy is :

Accepted Answer

Option C. In option (D) electron is removed from 4p subshell for 1^st ionization enthalpy, but in all other options electron is removed from 3p subshell. As 3p subshell is closer to nucleus than 4p, then attraction to the electrons in 3p subshell is more compared to the electrons in 4p subhell. That is why removal of electrons from 4p subshell is easy compared to 3p subshell. So among all the options, option (D) will have least ionization enthalpy.

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Periodic Table and Periodicity

More on Periodic Table and Periodicity