The electric field of light wave is given as
$\overrightarrow E = {10^{ - 3}}\cos \left( {{{2\pi x} \over {5 \times {{10}^{ - 7}}}} - 2\pi \times 6 \times {{10}^{14}}t} \right)\mathop x\limits^ \wedge {{\rm N} \over C}$
This
light falls on a metal plate of work function
2eV. The stopping potential of the photoelectrons
is :
Given, E (in eV) =
12375/(inÅ)