The electric field at a point associated with a light wave is given by E = 200 [sin (6 … 10¹⁵)t + sin (9 … 10¹⁵)t] Vm^…1 Given : h = 4.14 … 10^…15 eVs If this light falls on a metal surface having a work function of 2.50 eV, the maximum kinetic energy of the photoelectrons will be

Option D. Frequency of EM waves = … and …

Dual Nature of Radiation

JEE Main 2022 · 29 Jun, Evening shift · Q6646

PhysicsMedium145×since 2002Q6646

The electric field at a point associated with a light wave is given by E = 200 [sin (6

\times

10¹⁵)t + sin (9

\times

10¹⁵)t] Vm^

-

1 Given : h = 4.14

\times

10^

-

15 eVs If this light falls on a metal surface having a work function of 2.50 eV, the maximum kinetic energy of the photoelectrons will be