PhysicsEasy65×since 2002Q7835The distance travelled by a particle is related to time t as x=4t2x=4\mathrm{t}^2x=4t2. The velocity of the particle at t=5s is :-A25 ms−1\mathrm{25~ms^{-1}}25 ms−1B20 ms−1\mathrm{20~ms^{-1}}20 ms−1C8 ms−1\mathrm{8~ms^{-1}}8 ms−1D40 ms−1\mathrm{40~ms^{-1}}40 ms−1Check answerSkip