MathematicsMedium249×since 2002Q2397The distance of the point (1,−5,9)(1,-5,9)(1,−5,9) from the plane x−y+z=5x-y+z=5x−y+z=5 measured along the line x=y=zx=y=zx=y=z is :A103{{10} \over {\sqrt 3 }}310B203{20 \over 3}320C3103\sqrt {10}310D10310\sqrt {3}103Check answerSkip