MathematicsHard249×since 2002Q2466The distance of the point (−1,2,3)(-1,2,3)(−1,2,3) from the plane r⃗⋅(i^−2j^+3k^)=10\vec{r} \cdot(\hat{i}-2 \hat{j}+3 \hat{k})=10r⋅(i^−2j^+3k^)=10 parallel to the line of the shortest distance between the lines r⃗=(i^−j^)+λ(2i^+k^)\vec{r}=(\hat{i}-\hat{j})+\lambda(2 \hat{i}+\hat{k})r=(i^−j^)+λ(2i^+k^) and r⃗=(2i^−j^)+μ(i^−j^+k^)\vec{r}=(2 \hat{i}-\hat{j})+\mu(\hat{i}-\hat{j}+\hat{k})r=(2i^−j^)+μ(i^−j^+k^) is :A363 \sqrt{6}36B353 \sqrt{5}35C262 \sqrt{6}26D252 \sqrt{5}25Check answerSkip