MathematicsMedium249×since 2002Q2464The distance of the point (−1,9,−16-1,9,-16−1,9,−16) from the plane 2x+3y−z=52x+3y-z=52x+3y−z=5 measured parallel to the line x+43=2−y4=z−312{{x + 4} \over 3} = {{2 - y} \over 4} = {{z - 3} \over {12}}3x+4=42−y=12z−3 is :A132\sqrt22B26C202\sqrt22D31Check answerSkip