MathematicsHard249×since 2002Q2448The distance of the point (3, 2, −-−1) from the plane 3x−y+4z+1=03x - y + 4z + 1 = 03x−y+4z+1=0 along the line 2−x2=y−32=z+11{{2 - x} \over 2} = {{y - 3} \over 2} = {{z + 1} \over 1}22−x=2y−3=1z+1 is equal to :A9B6C3D2Check answerSkip