MathematicsEasy249×since 2002Q2500The distance of line 3y−2z−1=0=3x−z+43y - 2z - 1 = 0 = 3x - z + 43y−2z−1=0=3x−z+4 from the point (2, −-−1, 6) is :A26\sqrt {26}26B252\sqrt 525C262\sqrt 626D424\sqrt 242Check answerSkip