PhysicsEasy156×since 2002Q8240The dimension of B22μ0{{{B^2}} \over {2{\mu _0}}}2μ0B2, where B is magnetic field and μ0{{\mu _0}}μ0 is the magnetic permeability of vacuum, is :AML²T^–2BMLT^–2CML⁻¹T^–2DML²T^–1Check answerSkip