ChemistryEasy113×since 2002Q2114The de-Broglie's wavelength of electron present in first Bohr orbit of 'H' atom is :A0.529 A∘\mathop {\rm A}\limits^ \circA∘B2π\piπ ×\times× 0.529 A∘\mathop {\rm A}\limits^ \circA∘C0.5292π{{0.529} \over {2\pi }}2π0.529 A∘\mathop {\rm A}\limits^ \circA∘D4 ×\times× 0.529 A∘\mathop {\rm A}\limits^ \circA∘Check answerSkip