MathematicsMedium249×since 2002Q2401The coordinates of the foot of the perpendicular from the point (1, −-−2, 1) on the plane containing the lines, x+16=y−17=z−38{{x + 1} \over 6} = {{y - 1} \over 7} = {{z - 3} \over 8}6x+1=7y−1=8z−3 and x−13=y−25=z−37,{{x - 1} \over 3} = {{y - 2} \over 5} = {{z - 3} \over 7},3x−1=5y−2=7z−3, is :A(2, −-−4, 2)B(−-− 1, 2, −-−1)C(0, 0, 0)D(1, 1, 1)Check answerSkip