MathematicsEasy115×since 2008Q4392The converse of ((∼p)∧q)⇒r((\sim p) \wedge q) \Rightarrow r((∼p)∧q)⇒r isA((∼p)∨q)⇒r((\sim p) \vee q) \Rightarrow r((∼p)∨q)⇒rB(∼r)⇒p∧q(\sim \mathrm{r}) \Rightarrow \mathrm{p} \wedge \mathrm{q}(∼r)⇒p∧qC(p∨(∼q))⇒(∼r)(\mathrm{p} \vee(\sim \mathrm{q})) \Rightarrow(\sim \mathrm{r})(p∨(∼q))⇒(∼r)D(∼r)⇒((∼p)∧q)(\sim \mathrm{r}) \Rightarrow((\sim \mathrm{p}) \wedge \mathrm{q})(∼r)⇒((∼p)∧q)Check answerSkip