MathematicsHard115×since 2008Q4369The conditional statement ((p∧q)→((∼p)∨r))∨(((∼p)∨r)→(p∧q))((p \wedge q) \to (( \sim p) \vee r)) \vee ((( \sim p) \vee r) \to (p \wedge q))((p∧q)→((∼p)∨r))∨(((∼p)∨r)→(p∧q)) is :Aa tautologyBa contadictionCequivalent to p∧qp \wedge qp∧qDequivalent to (∼p)∨r( \sim p) \vee r(∼p)∨rCheck answerSkip