MathematicsMedium115×since 2008Q4387The compound statement (∼(P∧Q))∨((∼P)∧Q)⇒((∼P)∧(∼Q))\left( { \sim (P \wedge Q)} \right) \vee \left( {( \sim P) \wedge Q} \right) \Rightarrow \left( {( \sim P) \wedge ( \sim Q)} \right)(∼(P∧Q))∨((∼P)∧Q)⇒((∼P)∧(∼Q)) is equivalent toA((∼P)∨Q)∧(∼Q)(( \sim P) \vee Q) \wedge ( \sim Q)((∼P)∨Q)∧(∼Q)B(∼Q)∨P( \sim Q) \vee P(∼Q)∨PC((∼P)∨Q)∧((∼Q)∨P)(( \sim P) \vee Q) \wedge (( \sim Q) \vee P)((∼P)∨Q)∧((∼Q)∨P)D(∼P)∨Q( \sim P) \vee Q(∼P)∨QCheck answerSkip