MathematicsMedium178×since 2002Q5211The common difference of the A.P. b₁, b₂, … , b_m is 2 more than the common difference of A.P. a₁, a₂, …, a_n. If a_40 = –159, a₁₀₀ = –399 and b₁₀₀ = a₇₀, then b₁ is equal to :A127B81C–127D-81Check answerSkip