MathematicsMedium128×since 2002Q5511The combined equation of the two lines ax+by+c=0ax+by+c=0ax+by+c=0 and a′x+b′y+c′=0a'x+b'y+c'=0a′x+b′y+c′=0 can be written as (ax+by+c)(a′x+b′y+c′)=0(ax+by+c)(a'x+b'y+c')=0(ax+by+c)(a′x+b′y+c′)=0. The equation of the angle bisectors of the lines represented by the equation 2x2+xy−3y2=02x^2+xy-3y^2=02x2+xy−3y2=0 is :A3x2+xy−2y2=03{x^2} + xy - 2{y^2} = 03x2+xy−2y2=0Bx2−y2−10xy=0{x^2} - {y^2} - 10xy = 0x2−y2−10xy=0Cx2−y2+10xy=0{x^2} - {y^2} + 10xy = 0x2−y2+10xy=0D3x2+5xy+2y2=03{x^2} + 5xy + 2{y^2} = 03x2+5xy+2y2=0Check answerSkip