MathematicsHard115×since 2008Q4363The boolean expression (∼(p∧q))∨q( \sim (p \wedge q)) \vee q(∼(p∧q))∨q is equivalent to :Aq→(p∧q)q \to (p \wedge q)q→(p∧q)Bp→qp \to qp→qCp→(p→q)p \to (p \to q)p→(p→q)Dp→(p∨q)p \to (p \vee q)p→(p∨q)Check answerSkip