MathematicsMedium115×since 2008Q4348The Boolean expression (p∧∼q)⇒(q∨∼p)(p \wedge \sim q) \Rightarrow (q \vee \sim p)(p∧∼q)⇒(q∨∼p) is equivalent to :Aq⇒pq \Rightarrow pq⇒pBp⇒qp \Rightarrow qp⇒qC∼q⇒p\sim q \Rightarrow p∼q⇒pDp⇒ ∼qp \Rightarrow \, \sim qp⇒∼qCheck answerSkip